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x^2-4/3x-8/3=0
Domain of the equation: 3x!=0We calculate fractions
x!=0/3
x!=0
x∈R
x^2=0
a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{2}=0$
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